Learning Target:
Students will be able to explain why titrations are done in a lab setting.
Students will apply their knowledge of acids and bases to do a titration with calculations.
Students will be able to explain why titrations are done in a lab setting.
Students will apply their knowledge of acids and bases to do a titration with calculations.
Titration Lab-Acid and Base Neutralization
Question: A 25 ml solution of 0.5 M NaOH is titrated until neutralized into a 50 ml sample of HCl. What was the concentration of the HCl?
Solution: same equation used on previous page, except now we are going from an acid to a base instead of an acid to another concentration of acid.
M(acid) x V(acid) = M(base) x V(base)
where
M (acid) = concentration of the acid
V (acid) = volume of the acid
M (base) = concentration of the base
V (base) = volume of the base
Solution: same equation used on previous page, except now we are going from an acid to a base instead of an acid to another concentration of acid.
M(acid) x V(acid) = M(base) x V(base)
where
M (acid) = concentration of the acid
V (acid) = volume of the acid
M (base) = concentration of the base
V (base) = volume of the base
For the lab below answer the prelab questions, then write out the purpose of the lab, the materials needed, the procedure in your own words and a hypothesis for full credit.